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12x^2-76x-78=0
a = 12; b = -76; c = -78;
Δ = b2-4ac
Δ = -762-4·12·(-78)
Δ = 9520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9520}=\sqrt{16*595}=\sqrt{16}*\sqrt{595}=4\sqrt{595}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-4\sqrt{595}}{2*12}=\frac{76-4\sqrt{595}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+4\sqrt{595}}{2*12}=\frac{76+4\sqrt{595}}{24} $
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